Factorization

Important Questions

Class 10 Mathematics Chapter 7, Factorization is a crucial topic in ICSE Class 10 mathematics. It involves breaking down algebraic expressions or numbers into their constituent factors. Understanding factorization is essential as it forms the foundation for many other mathematical concepts. Here are some factorisation class 10 ICSE important questions.

Table of Contents

Factorization as we study in factorisation class 10 ICSE is the process of expressing a number or algebraic expression as the product of its factors. Factors are numbers or expressions that multiply together to yield the original number or expression. The main goal of factorization is to simplify complex expressions, solve equations, and understand the underlying structure of mathematical concepts.

**Common Factorization Techniques:**

**Common Factors:** Identifying and factoring out the common factors shared by multiple terms in an expression.

**Example:** Factorize 6x + 9y. The common factor is 3, so the expression becomes 3(2x + 3y).

**Difference of Squares:** Recognizing expressions in the form of a^2 – b^2 and factoring them as (a + b)(a – b).

**Example:** Factorize x^2 – 9. The expression factors as (x + 3)(x – 3).

In ICSE Class 10 mathematics, factorization refers to the process of expressing an algebraic expression or a number as the product of its constituent factors. Factors are numbers or algebraic expressions that, when multiplied together, result in the original expression or number. Factorization is an essential skill in mathematics and is used to simplify expressions, solve equations, and understand the underlying structure of mathematical concepts.
For example, consider the algebraic expression 2x^2 + 4x. Factorization of this expression involves finding two expressions that, when multiplied, result in 2x^2 + 4x. In this case, the factors are 2x and (x + 2), so the factorization is:
2x^2 + 4x = 2x(x + 2).
Factorization is also used to break down numbers into their prime factors. For instance, the prime factorization of the number 12 is:
12 = 2 * 2 * 3.

(b) 52

(c) -26

(d) -24

**Ans.** (b) 52

**Explanation:**

Let,

p(x) = 6x^3+ x^2 – 2x + 4 \\
\text{When,} \\
\text{p(x) is divided by x – 2,} \\
\text{Remainder = p(x = 2)} \\
= 6(2)^3 + (2)^2– 2(2) + 4 \\
= 48 + 4 – 4 + 4 = 52

(b) 12

(c) 10

(d) 16

**Ans.** (d) 16

**Explanation:**

Let,

f(x) = 3x^3– x^2 – px – 4 \space \space ...(i) \\
\text{Since, (x + 2) is a factor of f(x), f(–2) = 0} \\
⇒ 3(–2)^3 – (–2)^3 – p(–2) – 4 = 0 \\
⇒ –24 – 4 + 2p – 4 = 0

⇒ 2p = 32

⇒ p = 16

(ii) with the value of p, factorize the above expression completely.

**Explanation:**

Given expression is 2x^3 – x^2 – px – 2 and x – 2 is the factor.

(i) x – 2 = 0, x = 2 in expression

\\2 (2)^3 – (2)^2 – p (2) – 2 = 0\\
⇒ 16 – 4 – 2p – 2 = 0

⇒ 10 – 2p = 0

⇒ p = 5

(ii) Putting the value of p

(2x^3 + x^2 + 1) (x – 2) or (2x + 1) (x + 1) (x – 2).

(ii) and find their H.C.F as 𝑔(𝑥).

(iii) hence prove that: 𝑝(𝑥). 𝑞(𝑥) = 𝑓(𝑥). 𝑔(𝑥)

**Explanation:**

(i) For p (x), we have to find all possible factors of the constant -6

(By factor theorem, we have:)

Factors of - 6 are ∓1, ∓2, ∓3, ∓6, etc. and on putting the value in p (x) we get:

By hit and trial: for x = 1 we get p(i) = 13 - 6(1)^2 +11(1)-6 = 0.
Which clearly shows that (x-1) is a factor of p (x).

∴ on dividing p(x) by (x-1)will give:

p(x)=(x - 1)(x - 2)(x - 3)...(A)

Similarly solving for q(x) we have:

q(x)=(x - 2)(x - 3)(x - 1)...(B)

∴ L.C.M. = (x - 1)(x - 2)(x - 3)(x + 1)...(c)

**Explanation:**

Let,

P (x) = 2x^3 + ax^2 + bx – 2 \\
\text{when} \\
\text{P(x) is divided by 2x – 3}\\
P\begin{pmatrix} \frac{3}{2} \end{pmatrix} =2 \begin{pmatrix} \frac{3}{2} \end{pmatrix}^3 +a \begin{pmatrix} \frac{3}{2} \end{pmatrix}^2 +b \begin{pmatrix} \frac{3}{2} \end{pmatrix} -2 = 7 \\
= \frac{27}{4} + \frac{9}{4} a + \frac{3}{2} b - 2 = 7
= 9a + 6b = 28 + 8 – 27

= 9a + 6b = 9

= 3a + 2b = 3 …(i)

Similarly when P(x) is divided by x + 2

⇒ x = – 2

∴ 2(– 2)3 + a(– 2)2 + b(– 2) – 2 = 0
⇒ – 16 + 4a – 2b – 2 = 0

⇒ 4a – 2b = 18 …(ii)

On solving equations (i) and (ii)

3a + 2b = 3

\underline{4a – 2b = 18}
(On adding (ii)

7a = 21

a = 3

On substituting value of a in equation (i)

3 × 3 + 2b = 3

2b = 3 – 9

b =\frac{-6}{2}
=-3b = – 3a = 3, b = – 3

On substituting value of a and b

2x^3 + 3x^2 – 3x – 2
When x + 2 is a factor

= (x – 1) (2x + 1)

Hence, required factors are

(x – 1) (x + 2) (2x + 1)

Chapter No. | Chapter Name |
---|---|

Chapter 1 | Goods and Service Tax (GST) |

Chapter 2 | Banking |

Chapter 3 | Shares and Dividends |

Chapter 4 | Linear inequations |

Chapter 5 | Quadratic Equations in one variable |

Chapter 6 | Ratio and proportion |

Chapter 7 | Factorization |

Chapter 8 | Matrices |

Chapter 9 | Arithmetic Progression |

Chapter 10 | Geometric Progression |

Chapter 11 | Coordinate Geometry |

Chapter 12 | Reflection |

Chapter 13 | Similarity |

Chapter 14 | Loci |

Chapter 15 | Circles |

Chapter 16 | Constructions |

Chapter 17 | Mensuration |

Chapter 18 | Trigonometry |

Chapter 19 | Statistics |

Chapter 20 | Probability |

The chapter factorization class 10 ICSE is a foundational and pivotal topic that serves as a cornerstone for various mathematical concepts and practical applications. Mastering these factorisation class 10 ICSE important questions equips you with valuable problem-solving skills for everyday situations, making it a crucial part of your math education.

Ans: Factorization is the process of expressing an algebraic expression or a number as the product of its constituent factors. It is crucial in mathematics for simplifying expressions, solving equations, and understanding mathematical relationships.

Ans: Prime factors are the smallest prime numbers that multiply together to give a given number. To find them, you can use techniques like prime factorization or factor tree diagrams.

Ans: Algebraic factorization involves breaking down algebraic expressions into their constituent factors, while numerical factorization involves finding the prime factors of a number.

Ans: You can factorize quadratic trinomials using techniques like the product-sum method or trial and error to find two binomials that multiply to the trinomial.

Ans: A perfect square trinomial is the square of a binomial expression. It is factorized as the square of the binomial.

Chapter Wise Important Questions for ICSE Board Class 10 Mathematics |
---|

Goods and Service Tax (GST) |

Banking |

Shares and Dividends |

Linear inequations |

Quadratic Equations in one variable |

Ratio and proportion |

Factorization |

Matrices |

Arithmetic Progression |

Geometric Progression |

Coordinate Geometry |

Reflection |

Similarity |

Loci |

Circles |

Constructions |

Mensuration |

Trigonometry |

Statistics |

Probability |

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