Table of Contents
Ans. (c) \hat{i} + \hat{2j}\\[4.5 bp]
Ans. (c) 7
Explanation:
Vector, V \rightarrow \space 6\hat{i} + 2\hat{j} + 3\hat{k} \\
Magnitude of the vector, V;
\\|V| = \sqrt{(6^2 + 2^2 + 3^2)} = \sqrt{(36+4+9)} = \sqrt{49} = 7
Explanation:
Two vectors can have the same magnitude.
Magnitude of the vector \hat{i} - 2\hat{j} + \hat{k} is equal to the magnitude of the vector
2\hat{i} + \hat{j} - \hat{k}.
Explanation:
A =5\hat{i} + \hat{j} - 3\hat{k} \\[2.5 bp]
B = 3\hat{i} - 4\hat{j} + 7\hat{k} \\[2.5 bp]
A . B = (5\hat{i} + \hat{j} - 3\hat{k}).(3\hat{i} - 4\hat{j} + 7\hat{k})\\[4.5 bp]
= 5 · 3 + 1 · (-4) + (-3) · 7
= 15 – 4 – 21
= -10
Explanation:
Projection of \hat{i} - \hat{j}
on the vector \hat{i} + \hat{j} \\[4.5 bp]
(\hat{i} - \hat{j}).\dfrac{(\hat{i} + \hat{j})}{|\hat{i} + \hat{j}|} = 0
| Chapter No. | Chapter Name |
|---|---|
| Chapter 1 | Relations and Functions |
| Chapter 2 | Inverse Trigonometric Functions |
| Chapter 3 | Matrices |
| Chapter 4 | Determinants |
| Chapter 5 | Continuity and Differentiability |
| Chapter 6 | Applications of Derivatives |
| Chapter 7 | Integrals |
| Chapter 8 | Applications of the Integrals |
| Chapter 9 | Differential Equations |
| Chapter 10 | Vectors |
| Chapter 11 | Three - dimensional Geometry |
| Chapter 12 | Linear Programming |
| Chapter 13 | Probability |
| Chapter Wise Important Questions for CBSE Board Class 12 Maths |
|---|
| Relations and Functions |
| Inverse Trigonometric Functions |
| Matrices |
| Determinants |
| Continuity and Differentiability |
| Applications of Derivatives |
| Integrals |
| Applications of the Integrals |
| Differential Equations |
| Vectors |
| Three - dimensional Geometry |
| Linear Programming |
| Probability |
CBSE Important Questions Class 10
ICSE Important Questions Class 10
CBSE Important Questions Class 10
ICSE Important Questions Class 10