Table of Contents
Ans. (b) 0.195
Explanation:
1^{st} black ball drawn at random the probability = \dfrac{8}{13} \\[4.5 bp]
2^{nd} black ball drawn at random the probability = \dfrac{7}{12} \\[4.5 bp]
3^{rd} black ball drawn at random the probability = \dfrac{6}{11} \\[4.5 bp]
\text{P =} \left(\dfrac{8}{13}\right) × \left(\dfrac{7}{12}\right) × \left(\dfrac{6}{11}\right)\\[4.5 bp]
\text{So the total probability = }\dfrac{28}{(13×11)}\\[4.5 bp]
\text{= 0.195 }
Ans. (c)
Explanation:
A = {2, 4, 6, 8}
B = {8}
\\ \text{P(A) }= \dfrac{4}{9}, \text{ P(B) } = \dfrac{1}{9},\text{ A ∩ B = {8}, P(A ∩ B) }= \dfrac{1}{9}\\[4.5 bp]
P\left(\dfrac{A}{B}\right) = P\dfrac{\text{(A ∩ B)}}{\text{P(B)}} = \dfrac{\left(\dfrac{1}{9} \right)}{\left(\dfrac{1}{9}\right)} = 1
Explanation:
Let A and B be two independent events. Then,
P(A ∩ B) = P(A) × P(B) = \left(\dfrac{3}{8}\right) × \left(\dfrac{2}{5}\right) = \left(\dfrac{6}{40}\right) = \dfrac{3}{20}.
Explanation:
Here, P(B) = \dfrac{3}{5}, \text{P(A|B)} = \dfrac{1}{2}\text{ and P(A ∪ B) }= \dfrac{4}{5}\\[4.5 bp]
\text{P(A|B) = } \dfrac{P(A ∪ B)}{P(B)}\\[4.5 bp]
⇒ \dfrac{1}{2} = \dfrac{P(A ∪ B)}{P(B)}\\[4.5 bp]
⇒ P(A ∩ B) = \left(\dfrac{3}{5}\right) x \left(\dfrac{1}{2}\right) = \dfrac{3}{10} \\[4.5 bp]
and P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
⇒ \dfrac{4}{5} = \text{P(A) }+ \dfrac{3}{5} - \dfrac{3}{10} \\[4.5 bp]
\text{P(A) =} \dfrac{4}{5} - \dfrac{3}{5} + \dfrac{3}{10}\\[4.5 bp]
= \dfrac{(8 - 6 + 3)}{10}\\[4.5 bp]=\dfrac{1}{2} .
Explanation:
Let A, B, C be the respective events of solving the problem.
Then, \text{ P(A) }= \dfrac{1}{2} ,\text{ P(B) = } \dfrac{1}{3} \text{ and P(C) =}\dfrac{1}{4}.\\ Here, A, B, C are independent events.
Problem is solved if at least one of them solves the problem.
Required probability = P(A∪B∪C)
= 1 - P(A’) P(B’) P(C’)
= 1- \left(1 - \dfrac{1}{2}\right)\left(1 - \dfrac{1}{3}\right)\left(1 - \dfrac{1}{4}\right)\\[4.5 bp]
= 1- \left(\dfrac{1}{2}×\dfrac{2}{3}×\dfrac{3}{4}\right)\\[4.5 bp]
= 1- \dfrac{1}{4} = \dfrac{3}{4}.
Chapter No. | Chapter Name |
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Chapter 1 | Relations and Functions |
Chapter 2 | Inverse Trigonometric Functions |
Chapter 3 | Matrices |
Chapter 4 | Determinants |
Chapter 5 | Continuity and Differentiability |
Chapter 6 | Applications of Derivatives |
Chapter 7 | Integrals |
Chapter 8 | Applications of the Integrals |
Chapter 9 | Differential Equations |
Chapter 10 | Vectors |
Chapter 11 | Three - dimensional Geometry |
Chapter 12 | Linear Programming |
Chapter 13 | Probability |
Chapter Wise Important Questions for CBSE Board Class 12 Maths |
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Relations and Functions |
Inverse Trigonometric Functions |
Matrices |
Determinants |
Continuity and Differentiability |
Applications of Derivatives |
Integrals |
Applications of the Integrals |
Differential Equations |
Vectors |
Three - dimensional Geometry |
Linear Programming |
Probability |
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