Table of Contents
Ans. (c) 2
Explanation:
Differential equation y’’ + 5y’ + 6 = 0.
The highest order derivative present in the differential equation is y’’. Hence, the order is 2.
Ans. (d) 0
Explanation:
Particular solution of differential equation of any order, does not have any arbitrary constant.
Explanation:
The given function is y = a cos x + b sin x … (1)
Differentiating both sides of equation (1) with respect to x,
\dfrac{dy}{dx} = – a sin x + b cos x
\\[4.5 bp] \dfrac{d^2y}{dx^2} = – a cos x – b sin x
LHS = \dfrac{d^2y}{dx^2} + y
= – a cos x – b sin x + a cos x + b sin x = 0 = RHS
Hence, the given function is a solution to the given differential equation.
Explanation:
y = mx be the family of lines through the origin.
Therefore, \dfrac{dy}{dx} \text{= m} \\[2.5 bp]
Eliminating m, (substituting m = \dfrac{y}{x} )\\[4.5 bp]
\text{y =} \left(\dfrac{dy}{dx}\right) .\text{ x}\\[4.5 bp]
\text{x. }\dfrac{dy}{dx}\text{ – y = 0}
Explanation:
Here P = - \dfrac{3}{x}, \text{Q = x}^2 \\[4.5 bp]
Integrating factor= e^{∫\text{P dx}} \\[4.5 bp]
= e^{∫-\frac{3}{x} dx}\\[4.5 bp]
= e^{–\text{3 log x}}\\[4.5 bp]
= x^{–3}
Chapter No. | Chapter Name |
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Chapter 1 | Relations and Functions |
Chapter 2 | Inverse Trigonometric Functions |
Chapter 3 | Matrices |
Chapter 4 | Determinants |
Chapter 5 | Continuity and Differentiability |
Chapter 6 | Applications of Derivatives |
Chapter 7 | Integrals |
Chapter 8 | Applications of the Integrals |
Chapter 9 | Differential Equations |
Chapter 10 | Vectors |
Chapter 11 | Three - dimensional Geometry |
Chapter 12 | Linear Programming |
Chapter 13 | Probability |
Chapter Wise Important Questions for CBSE Board Class 12 Maths |
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Relations and Functions |
Inverse Trigonometric Functions |
Matrices |
Determinants |
Continuity and Differentiability |
Applications of Derivatives |
Integrals |
Applications of the Integrals |
Differential Equations |
Vectors |
Three - dimensional Geometry |
Linear Programming |
Probability |
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